XSL: A "showAll" template - unpacking XML node

This XSL template "showAll" will show the contents of a node.

Call it this way:
<xsl:call-template name="showAll">
<xsl:with-param name="showText" select="1" />
</xsl:call-template>

Where the param "showText" decides if you wish to see the text contents from
the nodes.

Here is the template:

<xsl:template name="showAll">
  <xsl:param name="showText" />
  <div style="padding-left: 10px; border-left: dotted 1px #e0e0e0;">
    <xsl:for-each select="*">
      <div style="padding-left: 10px;">
        &lt;<xsl:value-of select="name(.)"/>
        <xsl:for-each select="@*">
          &#160;<xsl:value-of select="name(.)"/>="<xsl:value-of select="."/>"
        </xsl:for-each>&gt;
        <xsl:if test="$showText=1">
          <xsl:value-of select="text()"/>
        </xsl:if>
        <xsl:if test ="count(*)>0">
          <br />
          <xsl:call-template name="showAll">
            <xsl:with-param name="showText" select="$showText" />
          </xsl:call-template>
        </xsl:if>
        <xsl:if test ="string-length(.)=0
and $showText!=1">
          /&gt;<br />
        </xsl:if>
        <xsl:if test ="string-length(.)>0">
          &lt;/<xsl:value-of select="name(.)" />&gt;<br />
        </xsl:if>
      </div>
    </xsl:for-each>
  </div>
</xsl:template>